PCI: keystone: Fix if-statement expression in ks_pcie_quirk()
[ Upstream commit 6188a1c762eb9bbd444f47696eda77a5eae6207a ] Follow-Up Fix: CVE-2024-47756 This code accidentally uses && where || was intended. It potentially results in a NULL dereference. Thus, fix the if-statement expression to use the correct condition. Fixes: 86f271f22bbb ("PCI: keystone: Add workaround for Errata #i2037 (AM65x SR 1.0)") Link: https://lore.kernel.org/linux-pci/1b762a93-e1b2-4af3-8c04-c8843905c279@stanley.mountain Signed-off-by: Dan Carpenter <dan.carpenter@linaro.org> [kwilczynski: commit log] Signed-off-by: Krzysztof Wilczyński <kwilczynski@kernel.org> Reviewed-by: Manivannan Sadhasivam <manivannan.sadhasivam@linaro.org> Reviewed-by: Siddharth Vadapalli <s-vadapalli@ti.com> Signed-off-by: Sasha Levin <sashal@kernel.org> Signed-off-by: Huang Cun <cunhuang@tencent.com> Signed-off-by: Jianping Liu <frankjpliu@tencent.com>
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@ -595,7 +595,7 @@ static void ks_pcie_quirk(struct pci_dev *dev)
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*/
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if (pci_match_id(am6_pci_devids, bridge)) {
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bridge_dev = pci_get_host_bridge_device(dev);
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if (!bridge_dev && !bridge_dev->parent)
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if (!bridge_dev || !bridge_dev->parent)
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return;
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ks_pcie = dev_get_drvdata(bridge_dev->parent);
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