i40e: Bypass timeout recovery level 0 so as to not cause MDD
When a Tx hang happens, usually the Tx queue disable fails. At this point if we try to recover by a VSI reinit the HW gets unhappy and we get a Malicious Driver Detect (MDD) event. HW expects a PF reset if a queue disable fails, if we don't do a PF reset and restart the queue we get an MDD. This patch makes sure we do a PF reset on Tx hang and that way we avoid any MDD because of Tx queue disable failure. Change-ID: I665ab6223577c788da857ee2132e733dc9a451e4 Signed-off-by: Anjali Singhai Jain <anjali.singhai@intel.com> Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
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@ -278,7 +278,7 @@ static void i40e_tx_timeout(struct net_device *netdev)
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pf->tx_timeout_count++;
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if (time_after(jiffies, (pf->tx_timeout_last_recovery + HZ*20)))
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pf->tx_timeout_recovery_level = 0;
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pf->tx_timeout_recovery_level = 1;
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pf->tx_timeout_last_recovery = jiffies;
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netdev_info(netdev, "tx_timeout recovery level %d\n",
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pf->tx_timeout_recovery_level);
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@ -6826,6 +6826,8 @@ static int i40e_sw_init(struct i40e_pf *pf)
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pf->irq_pile->num_entries = pf->hw.func_caps.num_msix_vectors;
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pf->irq_pile->search_hint = 0;
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pf->tx_timeout_recovery_level = 1;
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mutex_init(&pf->switch_mutex);
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sw_init_done:
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