xfs: compare btree block keys to parent block's keys during scrub
When we're done checking all the records/keys in a btree block, compute the low and high key of the block and compare them to the associated key in the parent btree block. Signed-off-by: Darrick J. Wong <darrick.wong@oracle.com> Reviewed-by: Brian Foster <bfoster@redhat.com>
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@ -2027,7 +2027,7 @@ error0:
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}
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/* Find the high key storage area from a regular key. */
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STATIC union xfs_btree_key *
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union xfs_btree_key *
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xfs_btree_high_key_from_key(
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struct xfs_btree_cur *cur,
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union xfs_btree_key *key)
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@ -2101,7 +2101,7 @@ xfs_btree_get_node_keys(
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}
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/* Derive the keys for any btree block. */
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STATIC void
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void
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xfs_btree_get_keys(
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struct xfs_btree_cur *cur,
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struct xfs_btree_block *block,
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@ -541,5 +541,9 @@ int64_t xfs_btree_diff_two_ptrs(struct xfs_btree_cur *cur,
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void xfs_btree_get_sibling(struct xfs_btree_cur *cur,
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struct xfs_btree_block *block,
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union xfs_btree_ptr *ptr, int lr);
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void xfs_btree_get_keys(struct xfs_btree_cur *cur,
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struct xfs_btree_block *block, union xfs_btree_key *key);
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union xfs_btree_key *xfs_btree_high_key_from_key(struct xfs_btree_cur *cur,
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union xfs_btree_key *key);
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#endif /* __XFS_BTREE_H__ */
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@ -357,6 +357,50 @@ xfs_scrub_btree_get_block(
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return xfs_scrub_btree_block_check_siblings(bs, *pblock);
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}
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/*
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* Check that the low and high keys of this block match the keys stored
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* in the parent block.
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*/
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STATIC void
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xfs_scrub_btree_block_keys(
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struct xfs_scrub_btree *bs,
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int level,
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struct xfs_btree_block *block)
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{
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union xfs_btree_key block_keys;
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struct xfs_btree_cur *cur = bs->cur;
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union xfs_btree_key *high_bk;
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union xfs_btree_key *parent_keys;
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union xfs_btree_key *high_pk;
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struct xfs_btree_block *parent_block;
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struct xfs_buf *bp;
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if (level >= cur->bc_nlevels - 1)
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return;
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/* Calculate the keys for this block. */
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xfs_btree_get_keys(cur, block, &block_keys);
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/* Obtain the parent's copy of the keys for this block. */
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parent_block = xfs_btree_get_block(cur, level + 1, &bp);
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parent_keys = xfs_btree_key_addr(cur, cur->bc_ptrs[level + 1],
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parent_block);
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if (cur->bc_ops->diff_two_keys(cur, &block_keys, parent_keys) != 0)
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xfs_scrub_btree_set_corrupt(bs->sc, cur, 1);
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if (!(cur->bc_flags & XFS_BTREE_OVERLAPPING))
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return;
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/* Get high keys */
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high_bk = xfs_btree_high_key_from_key(cur, &block_keys);
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high_pk = xfs_btree_high_key_addr(cur, cur->bc_ptrs[level + 1],
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parent_block);
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if (cur->bc_ops->diff_two_keys(cur, high_bk, high_pk) != 0)
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xfs_scrub_btree_set_corrupt(bs->sc, cur, 1);
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}
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/*
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* Visit all nodes and leaves of a btree. Check that all pointers and
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* records are in order, that the keys reflect the records, and use a callback
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@ -418,6 +462,7 @@ xfs_scrub_btree(
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/* End of leaf, pop back towards the root. */
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if (cur->bc_ptrs[level] >
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be16_to_cpu(block->bb_numrecs)) {
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xfs_scrub_btree_block_keys(&bs, level, block);
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if (level < cur->bc_nlevels - 1)
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cur->bc_ptrs[level + 1]++;
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level++;
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@ -442,6 +487,7 @@ xfs_scrub_btree(
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/* End of node, pop back towards the root. */
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if (cur->bc_ptrs[level] > be16_to_cpu(block->bb_numrecs)) {
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xfs_scrub_btree_block_keys(&bs, level, block);
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if (level < cur->bc_nlevels - 1)
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cur->bc_ptrs[level + 1]++;
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level++;
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