XArray: Fix xa_erase of 2-byte aligned entries
xas_store() was interpreting the entry it found in the array as a node entry if the bottom two bits had value 2. That's only true if either the entry is in the root node or in a non-leaf node. Signed-off-by: Matthew Wilcox <willy@infradead.org>
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@ -1355,6 +1355,20 @@ static void check_align_1(struct xarray *xa, char *name)
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xa_destroy(xa);
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}
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static void check_align_2(struct xarray *xa, char *name)
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{
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int i;
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XA_BUG_ON(xa, !xa_empty(xa));
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for (i = 0; i < 8; i++) {
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XA_BUG_ON(xa, xa_store(xa, 0, name + i, GFP_KERNEL) != NULL);
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xa_erase(xa, 0);
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}
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XA_BUG_ON(xa, !xa_empty(xa));
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}
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static noinline void check_align(struct xarray *xa)
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{
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char name[] = "Motorola 68000";
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@ -1363,7 +1377,7 @@ static noinline void check_align(struct xarray *xa)
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check_align_1(xa, name + 1);
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check_align_1(xa, name + 2);
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check_align_1(xa, name + 3);
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// check_align_2(xa, name);
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check_align_2(xa, name);
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}
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static LIST_HEAD(shadow_nodes);
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@ -800,7 +800,7 @@ void *xas_store(struct xa_state *xas, void *entry)
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* entry is set to NULL.
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*/
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rcu_assign_pointer(*slot, entry);
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if (xa_is_node(next))
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if (xa_is_node(next) && (!node || node->shift))
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xas_free_nodes(xas, xa_to_node(next));
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if (!node)
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break;
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