MIPS: Alchemy: Remove direct access to prepare_count field of struct clk

Replacing it with a call to __clk_is_prepared(), which isn't entirely
equivalent but in practice shouldn't matter.

Signed-off-by: Tomeu Vizoso <tomeu.vizoso@collabora.com>
Reviewed-by: Stephen Boyd <sboyd@codeaurora.org>
Cc: Mike Turquette <mturquette@linaro.org>
Cc: Javier Martinez Canillas <javier.martinez@collabora.co.uk>
Cc: Manuel Lauss <manuel.lauss@gmail.com>
Cc: linux-mips@linux-mips.org
Cc: linux-kernel@vger.kernel.org
Patchwork: https://patchwork.linux-mips.org/patch/8120/
Signed-off-by: Ralf Baechle <ralf@linux-mips.org>
This commit is contained in:
Tomeu Vizoso 2014-10-20 15:40:01 +02:00 committed by Ralf Baechle
parent a45da56598
commit 24c71c83ed
1 changed files with 3 additions and 4 deletions

View File

@ -37,7 +37,6 @@
#include <linux/io.h>
#include <linux/clk-provider.h>
#include <linux/clkdev.h>
#include <linux/clk-private.h>
#include <linux/slab.h>
#include <linux/spinlock.h>
#include <linux/types.h>
@ -397,10 +396,10 @@ static long alchemy_clk_fgcs_detr(struct clk_hw *hw, unsigned long rate,
break;
/* if this parent is currently unused, remember it.
* XXX: I know it's a layering violation, but it works
* so well.. (if (!clk_has_active_children(pc)) )
* XXX: we would actually want clk_has_active_children()
* but this is a good-enough approximation for now.
*/
if (pc->prepare_count == 0) {
if (!__clk_is_prepared(pc)) {
if (!free)
free = pc;
}