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sched: Optimize build_sched_domains() for saving first SD node for a cpu 

We are saving first scheduling domain for a cpu in build_sched_domains() by
iterating over the nested sd->child list. We don't actually need to do it this
way.

tl will be equal to sched_domain_topology for the first iteration and so we can
set *per_cpu_ptr(d.sd, i) based on that.  So, save pointer to first SD while
running the iteration loop over tl's.

Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
Signed-off-by: Peter Zijlstra <peterz@infradead.org>
Link: http://lkml.kernel.org/r/fc473527cbc4dfa0b8eeef2a59db74684eb59a83.1370436120.git.viresh.kumar@linaro.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Viresh Kumar 2013-06-04 15:41:15 +05:30 committed by Ingo Molnar
parent 4a850cbefa
commit 22da956953
1 changed files with 2 additions and 5 deletions
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7
kernel/sched/core.c
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@ -5985,16 +5985,13 @@ static int build_sched_domains(const struct cpumask *cpu_map,
sd = NULL;
for (tl = sched_domain_topology; tl->init; tl++) {
sd = build_sched_domain(tl, cpu_map, attr, sd, i);
if (tl == sched_domain_topology)
*per_cpu_ptr(d.sd, i) = sd;
if (tl->flags & SDTL_OVERLAP || sched_feat(FORCE_SD_OVERLAP))
sd->flags |= SD_OVERLAP;
if (cpumask_equal(cpu_map, sched_domain_span(sd)))
break;
}
while (sd->child)
sd = sd->child;
*per_cpu_ptr(d.sd, i) = sd;
}
/* Build the groups for the domains */