Fix roundup_pow_of_two(1)
1 is a power of two, therefore roundup_pow_of_two(1) should return 1. It does in case the argument is a variable but in case it's a constant it behaves wrong and returns 0. Probably nobody ever did it so this was never noticed. Signed-off-by: Rolf Eike Beer <eike-kernel@sf-tec.de> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -159,7 +159,7 @@ unsigned long __roundup_pow_of_two(unsigned long n)
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#define roundup_pow_of_two(n) \
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( \
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__builtin_constant_p(n) ? ( \
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(n == 1) ? 0 : \
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(n == 1) ? 1 : \
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(1UL << (ilog2((n) - 1) + 1)) \
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) : \
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__roundup_pow_of_two(n) \
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