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libceph: fix error handling in handle_reply() 

We've tried to fix the error paths in this function before, but there
is still a hidden goto in the ceph_decode_need() macro which goes to the
wrong place.  We need to release the "req" and unlock a mutex before
returning.

Signed-off-by: Dan Carpenter <dan.carpenter@oracle.com>
Reviewed-by: Sage Weil <sage@inktank.com>
This commit is contained in:
Dan Carpenter 2013-08-15 08:51:58 +03:00 committed by Sage Weil
parent b314a90d8f
commit 1874119664
1 changed files with 3 additions and 3 deletions
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6
net/ceph/osd_client.c
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@ -1495,14 +1495,14 @@ static void handle_reply(struct ceph_osd_client *osdc, struct ceph_msg *msg,
dout("handle_reply %p tid %llu req %p result %d\n", msg, tid,
req, result);
ceph_decode_need(&p, end, 4, bad);
ceph_decode_need(&p, end, 4, bad_put);
numops = ceph_decode_32(&p);
if (numops > CEPH_OSD_MAX_OP)
goto bad_put;
if (numops != req->r_num_ops)
goto bad_put;
payload_len = 0;
ceph_decode_need(&p, end, numops * sizeof(struct ceph_osd_op), bad);
ceph_decode_need(&p, end, numops * sizeof(struct ceph_osd_op), bad_put);
for (i = 0; i < numops; i++) {
struct ceph_osd_op *op = p;
int len;
@ -1520,7 +1520,7 @@ static void handle_reply(struct ceph_osd_client *osdc, struct ceph_msg *msg,
goto bad_put;
}
ceph_decode_need(&p, end, 4 + numops * 4, bad);
ceph_decode_need(&p, end, 4 + numops * 4, bad_put);
retry_attempt = ceph_decode_32(&p);
for (i = 0; i < numops; i++)
req->r_reply_op_result[i] = ceph_decode_32(&p);