clk: ingenic/jz4725b: Fix "pll half" divider not read/written properly
The code was setting the bit 21 of the CPCCR register to use a divider of 2 for the "pll half" clock, and clearing the bit to use a divider of 1. This is the opposite of how this register field works: a cleared bit means that the /2 divider is used, and a set bit means that the divider is 1. Restore the correct behaviour using the newly introduced .div_table field. Signed-off-by: Paul Cercueil <paul@crapouillou.net> Signed-off-by: Stephen Boyd <sboyd@kernel.org>
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@ -37,6 +37,10 @@ static const u8 jz4725b_cgu_cpccr_div_table[] = {
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1, 2, 3, 4, 6, 8,
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};
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static const u8 jz4725b_cgu_pll_half_div_table[] = {
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2, 1,
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};
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static const struct ingenic_cgu_clk_info jz4725b_cgu_clocks[] = {
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/* External clocks */
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@ -70,7 +74,10 @@ static const struct ingenic_cgu_clk_info jz4725b_cgu_clocks[] = {
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[JZ4725B_CLK_PLL_HALF] = {
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"pll half", CGU_CLK_DIV,
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.parents = { JZ4725B_CLK_PLL, -1, -1, -1 },
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.div = { CGU_REG_CPCCR, 21, 1, 1, -1, -1, -1 },
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.div = {
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CGU_REG_CPCCR, 21, 1, 1, -1, -1, -1,
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jz4725b_cgu_pll_half_div_table,
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},
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},
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[JZ4725B_CLK_CCLK] = {
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