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KVM: x86: Allocate memslot resources during prepare_memory_region() 

Allocate the various metadata structures associated with a new memslot
during kvm_arch_prepare_memory_region(), which paves the way for
removing kvm_arch_create_memslot() altogether.  Moving x86's memory
allocation only changes the order of kernel memory allocations between
x86 and common KVM code.

Reviewed-by: Peter Xu <peterx@redhat.com>
Signed-off-by: Sean Christopherson <sean.j.christopherson@intel.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
Sean Christopherson 2020-02-18 13:07:19 -08:00 committed by Paolo Bonzini
parent 82307e676f
commit 0dab98b7ad
1 changed files with 9 additions and 4 deletions
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13
arch/x86/kvm/x86.c
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@ -9875,6 +9875,12 @@ void kvm_arch_free_memslot(struct kvm *kvm, struct kvm_memory_slot *free,
int kvm_arch_create_memslot(struct kvm *kvm, struct kvm_memory_slot *slot,
unsigned long npages)
{
return 0;
}
static int kvm_alloc_memslot_metadata(struct kvm_memory_slot *slot,
unsigned long npages)
{
int i;
@ -9966,10 +9972,9 @@ int kvm_arch_prepare_memory_region(struct kvm *kvm,
const struct kvm_userspace_memory_region *mem,
enum kvm_mr_change change)
{
if (change == KVM_MR_MOVE)
return kvm_arch_create_memslot(kvm, memslot,
mem->memory_size >> PAGE_SHIFT);
if (change == KVM_MR_CREATE || change == KVM_MR_MOVE)
return kvm_alloc_memslot_metadata(memslot,
mem->memory_size >> PAGE_SHIFT);
return 0;
}