ACPI / dock: Use acpi_device_enumerated() to check if dock is present
After commit202317a573
(ACPI / scan: Add acpi_device objects for all device nodes in the namespace) acpi_bus_get_device() will always return 0 for dock devices in dock_notify(), so the dock station docking code under ACPI_NOTIFY_DEVICE_CHECK will never be executed and docking will not work as a result of that. Fix the problem by making dock_notify() use acpi_device_enumerated() to check the presence of the device instead of checking the return value of acpi_bus_get_device(). Fixes:202317a573
(ACPI / scan: Add acpi_device objects for all device nodes in the namespace) Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
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@ -609,7 +609,7 @@ static int handle_eject_request(struct dock_station *ds, u32 event)
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static void dock_notify(struct dock_station *ds, u32 event)
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{
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acpi_handle handle = ds->handle;
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struct acpi_device *ad;
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struct acpi_device *adev = NULL;
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int surprise_removal = 0;
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/*
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@ -632,7 +632,8 @@ static void dock_notify(struct dock_station *ds, u32 event)
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switch (event) {
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case ACPI_NOTIFY_BUS_CHECK:
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case ACPI_NOTIFY_DEVICE_CHECK:
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if (!dock_in_progress(ds) && acpi_bus_get_device(handle, &ad)) {
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acpi_bus_get_device(handle, &adev);
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if (!dock_in_progress(ds) && !acpi_device_enumerated(adev)) {
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begin_dock(ds);
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dock(ds);
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if (!dock_present(ds)) {
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