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bpf: offload: make bpf_offload_dev_match() reject host+host case 

Daniel suggests it would be more logical for bpf_offload_dev_match()
to return false is either the program or the map are not offloaded,
rather than treating the both not offloaded case as a "matching
CPU/host device".

This makes no functional difference today, since verifier only calls
bpf_offload_dev_match() when one of the objects is offloaded.

Signed-off-by: Jakub Kicinski <jakub.kicinski@netronome.com>
Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
This commit is contained in:
Jakub Kicinski 2018-01-16 15:51:45 -08:00 committed by Daniel Borkmann
parent 4c38f74c91
commit 0a2d28ff51
1 changed files with 1 additions and 3 deletions
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4
kernel/bpf/offload.c
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@ -395,10 +395,8 @@ bool bpf_offload_dev_match(struct bpf_prog *prog, struct bpf_map *map)
struct bpf_prog_offload *offload;
bool ret;
if (!!bpf_prog_is_dev_bound(prog->aux) != !!bpf_map_is_dev_bound(map))
if (!bpf_prog_is_dev_bound(prog->aux) || !bpf_map_is_dev_bound(map))
return false;
if (!bpf_prog_is_dev_bound(prog->aux))
return true;
down_read(&bpf_devs_lock);
offload = prog->aux->offload;