finish FPFLU #127

This commit is contained in:
hli28146 2025-12-10 21:53:20 +08:00
parent f876a28ada
commit 722d6b2ca4
4 changed files with 278 additions and 0 deletions

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import torch
import torch.nn as nn
from torch.utils.cpp_extension import load_inline
cpp_source = """
#include <torch/extension.h>
torch::Tensor fpflu_cuda_forward(const torch::Tensor& input);
"""
cuda_source = """
#include <torch/extension.h>
#include <cuda_runtime.h>
#include <math.h>
#define BLOCK_SIZE 256
struct __align__(16) Float4 {
float x, y, z, w;
};
// FPFLU Logic
__device__ __forceinline__ float compute_fpflu(float x) {
if (x >= 0.0f) {
return x;
} else {
return x / (1.0f + x * x);
}
}
__global__ void fpflu_kernel(
float* __restrict__ output,
const float* __restrict__ input,
const int n)
{
const int idx = blockIdx.x * blockDim.x + threadIdx.x;
const int vec_n = n / 4;
int i = idx;
const int stride = blockDim.x * gridDim.x;
for (; i < vec_n; i += stride) {
Float4 in_vec = reinterpret_cast<const Float4*>(input)[i];
Float4 out_vec;
out_vec.x = compute_fpflu(in_vec.x);
out_vec.y = compute_fpflu(in_vec.y);
out_vec.z = compute_fpflu(in_vec.z);
out_vec.w = compute_fpflu(in_vec.w);
reinterpret_cast<Float4*>(output)[i] = out_vec;
}
int start_scalar = vec_n * 4;
int global_tid = blockIdx.x * blockDim.x + threadIdx.x;
int total_threads = gridDim.x * gridDim.x;
int current_idx = start_scalar + global_tid;
while (current_idx < n) {
output[current_idx] = compute_fpflu(input[current_idx]);
current_idx += total_threads;
}
}
torch::Tensor fpflu_cuda_forward(const torch::Tensor& input) {
TORCH_CHECK(input.is_cuda(), "Input must be a CUDA tensor");
TORCH_CHECK(input.is_contiguous(), "Input must be contiguous");
const int n = input.numel();
auto output = torch::empty_like(input);
const int vec_n = n / 4;
const int grid_size = (vec_n + BLOCK_SIZE - 1) / BLOCK_SIZE;
int final_grid = (grid_size < 1) ? 1 : grid_size;
if (final_grid > 65535) final_grid = 65535;
fpflu_kernel<<<final_grid, BLOCK_SIZE>>>(
output.data_ptr<float>(),
input.data_ptr<float>(),
n
);
return output;
}
"""
fpflu_op_module = load_inline(
name='fpflu_op',
cpp_sources=cpp_source,
cuda_sources=cuda_source,
functions=['fpflu_cuda_forward'],
verbose=False,
extra_cuda_cflags=['-O3']
)
class ModelNew(nn.Module):
def __init__(self):
super(ModelNew, self).__init__()
self.op = fpflu_op_module
def forward(self, input_tensor: torch.Tensor) -> torch.Tensor:
return self.op.fpflu_cuda_forward(input_tensor.contiguous())

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import torch
import torch.nn as nn
BATCH_SIZE = 4096
HIDDEN_DIM = 4096
SHAPE = (BATCH_SIZE, HIDDEN_DIM)
class FPFLU(nn.Module):
"""
Faster Power Function Linear Unit (FPFLU).
PFLU and FPFLU: Two novel non-monotonic activation functions in convolutional neural network
https://doi.org/10.1016/j.neucom.2020.11.068
"""
def __init__(self):
super(FPFLU, self).__init__()
def forward(self, x: torch.Tensor) -> torch.Tensor:
# PyTorch 原生实现
pos_part = x
neg_part = x / (1.0 + x.pow(2))
return torch.where(x >= 0, pos_part, neg_part)
class Model(nn.Module):
def __init__(self):
super(Model, self).__init__()
self.act = FPFLU()
def forward(self, x):
return self.act(x)
def get_inputs():
input_tensor = torch.randn(SHAPE, dtype=torch.float32) * 5.0
return [input_tensor.contiguous()]
def get_init_inputs():
return []

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Write a custom CUDA kernel to optimize `FPFLU` (Faster Power Function Linear Unit).
Formula:
f(x) = x if x >= 0
f(x) = x / (1 + x^2) if x < 0
This is a fast, non-monotonic activation that avoids expensive sqrt operations.
Problem Analysis:
1. Memory Bound: This is a point-wise activation with low arithmetic intensity. Performance is limited by memory bandwidth.
2. Operator Chaining: The PyTorch implementation using `torch.where` creates intermediate tensors.
Optimization Strategy: Fused Element-wise Kernel with Vectorization
1. One-Thread-per-Element: Map each element to a CUDA thread.
2. Vectorized Loads (float4): Use `float4` to process 128 bits per memory transaction.
3. Fused Fast Math:
- For each element `x`, check `if (x < 0)`.
- If true, compute `x * (1.0f / (1.0f + x*x))`.
- If false, result is `x`.
- Using reciprocal multiplication `x * rcp(1 + x*x)` can be faster.
4. One-Pass: Fuse all steps into a single read-compute-write kernel.
Here's an example to show you the syntax of inline embedding custom CUDA operators in torch: The example given architecture is:
```python
import torch
import torch.nn as nn
BATCH_SIZE = 4096
HIDDEN_DIM = 4096
SHAPE = (BATCH_SIZE, HIDDEN_DIM)
class FPFLU(nn.Module):
"""
Faster Power Function Linear Unit (FPFLU).
PFLU and FPFLU: Two novel non-monotonic activation functions in convolutional neural network
https://doi.org/10.1016/j.neucom.2020.11.068
"""
def __init__(self):
super(FPFLU, self).__init__()
def forward(self, x: torch.Tensor) -> torch.Tensor:
# PyTorch 原生实现
pos_part = x
neg_part = x / (1.0 + x.pow(2))
return torch.where(x >= 0, pos_part, neg_part)
class Model(nn.Module):
def __init__(self):
super(Model, self).__init__()
self.act = FPFLU()
def forward(self, x):
return self.act(x)
def get_inputs():
input_tensor = torch.randn(SHAPE, dtype=torch.float32) * 5.0
return [input_tensor.contiguous()]
def get_init_inputs():
return []

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###########################################################
# 性能和精度验证程序
###########################################################
import torch
import torch.nn as nn
import time
from FPFLU_torch import Model,get_inputs,get_init_inputs
from FPFLU_cuda import ModelNew
def run_benchmark():
# 检查 CUDA 是否可用
if not torch.cuda.is_available():
print("CUDA 不可用,请确保您有可用的 NVIDIA GPU 并已正确安装 PyTorch CUDA 版本。")
return
else:
device = torch.device("cuda")
# 初始化模型
init_inputs = get_init_inputs()
init_inputs = [
x.cuda(device=device) if isinstance(x, torch.Tensor) else x for x in init_inputs
]
inputs = get_inputs()
inputs = [
x.cuda(device=device) if isinstance(x, torch.Tensor) else x for x in inputs
]
torch_model = Model(*init_inputs).cuda()
cuda_model = ModelNew(*init_inputs).cuda()
torch_model.eval()
cuda_model.eval()
print("-------------------- 精度对齐验证 --------------------")
with torch.no_grad():
output_torch = torch_model( *inputs)
output_cuda = cuda_model(*inputs)
precision_flag = torch.allclose(output_torch, output_cuda,rtol=1e-03)
if precision_flag:
print("✅ 精度对齐:两个模型的输出结果非常接近。")
else:
print("❌ 精度不一致!")
print("\n-------------------- 性能加速比测试 --------------------")
num_iterations = 100
# PyTorch 模型计时
torch.cuda.synchronize()
start_time = time.time()
for _ in range(num_iterations):
_ = torch_model(*inputs)
torch.cuda.synchronize()
torch_time = (time.time() - start_time) / num_iterations
# 自定义 CUDA 内核计时
torch.cuda.synchronize()
start_time = time.time()
for _ in range(num_iterations):
_ = cuda_model(*inputs)
torch.cuda.synchronize()
cuda_time = (time.time() - start_time) / num_iterations
print(f"PyTorch torch.relu 平均执行时间: {torch_time:.6f}")
print(f"自定义 CUDA 内核 平均执行时间: {cuda_time:.6f}")
speedup = 0
if cuda_time > 0:
speedup = torch_time / cuda_time
print(f"加速比 (Speedup): {speedup:.2f}x")
else:
print("CUDA 内核执行时间为0无法计算加速比。")
return precision_flag,speedup
if __name__ == "__main__":
precision_flag,speedup = run_benchmark()