finish cross #9

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hli28146 2025-11-17 22:30:08 +08:00
parent f876a28ada
commit 5650da6b59
4 changed files with 247 additions and 0 deletions

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import torch
import torch.nn as nn
from torch.utils.cpp_extension import load_inline
# C++ 源代码
cpp_source = """
#include <torch/extension.h>
torch::Tensor cross_cuda_forward(const torch::Tensor& x, const torch::Tensor& y, int64_t dim);
"""
# CUDA 源代码
cuda_source = """
#include <torch/extension.h>
#include <cuda_runtime.h>
template <typename T>
__global__ void cross_kernel_stride(
T* output,
const T* x,
const T* y,
const int64_t num_vectors,
const int64_t dim_stride,
const int64_t slice_stride)
{{
// 每个线程负责一个完整的叉积计算
const int64_t idx = blockIdx.x * blockDim.x + threadIdx.x;
if (idx >= num_vectors) return;
// --- 使用 stride 计算基地址 ---
const T* x_vec = x + idx * slice_stride;
const T* y_vec = y + idx * slice_stride;
T* out_vec = output + idx * slice_stride;
// --- 使用 dim_stride 加载数据到寄存器 ---
const T x0 = x_vec[0];
const T x1 = x_vec[dim_stride];
const T x2 = x_vec[2 * dim_stride];
const T y0 = y_vec[0];
const T y1 = y_vec[dim_stride];
const T y2 = y_vec[2 * dim_stride];
out_vec[0] = x1 * y2 - x2 * y1;
out_vec[dim_stride] = x2 * y0 - x0 * y2;
out_vec[2 * dim_stride] = x0 * y1 - x1 * y0;
}}
torch::Tensor cross_cuda_forward(const torch::Tensor& x, const torch::Tensor& y, int64_t dim) {
auto sizes = x.sizes();
int ndim = x.dim();
if (dim < 0) dim += ndim;
TORCH_CHECK(x.is_cuda() && y.is_cuda(), "Inputs must be CUDA tensors");
TORCH_CHECK(x.sizes() == y.sizes(), "Input shapes must match");
TORCH_CHECK(x.is_contiguous() && y.is_contiguous(), "Inputs must be contiguous for this implementation");
TORCH_CHECK(sizes[dim] == 3, "Dimension for cross product must be 3");
// Stride 计算
const int64_t dim_stride = x.stride(dim);
const int64_t num_vectors = x.numel() / 3;
// 创建一个临时视图来计算 slice_stride
auto x_flat = x.transpose(dim, -1).flatten(0, -2);
const int64_t slice_stride = x_flat.stride(0);
auto output = torch::empty_like(x);
const int block_size = 256;
const int num_blocks = (num_vectors + block_size - 1) / block_size;
AT_DISPATCH_FLOATING_TYPES(x.scalar_type(), "cross_kernel_stride", ([&] {{
cross_kernel_stride<scalar_t><<<num_blocks, block_size>>>(
output.data_ptr<scalar_t>(),
x.data_ptr<scalar_t>(),
y.data_ptr<scalar_t>(),
num_vectors,
dim_stride,
slice_stride
);
}}));
return output;
}
"""
class ModelNew(nn.Module):
def __init__(self, dim):
super(ModelNew, self).__init__()
self.dim = dim
self.op = load_inline(
name='cross_op_stride',
cpp_sources=cpp_source,
cuda_sources=cuda_source,
functions=['cross_cuda_forward'],
verbose=False
)
def forward(self, x: torch.Tensor, y: torch.Tensor) -> torch.Tensor:
return self.op.cross_cuda_forward(x, y, self.dim)

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import torch
import torch.nn as nn
# --- 用于基准测试的配置 ---
BATCH_SIZE = 512
VECTORS = 8192
SHAPE = (BATCH_SIZE, VECTORS, 3)
DIM = -1
class Model(nn.Module):
"""
使用 PyTorch 内置的 torch.linalg.cross 作为基准模型
"""
def __init__(self, dim):
super(Model, self).__init__()
self.dim = dim
def forward(self, x: torch.Tensor, y: torch.Tensor) -> torch.Tensor:
return torch.linalg.cross(x, y, dim=self.dim)
def get_inputs():
x = torch.randn(SHAPE, dtype=torch.float32)
y = torch.randn(SHAPE, dtype=torch.float32)
return [x.contiguous(), y.contiguous()]
def get_init_inputs():
return [DIM]

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S1/hli28146_#9/prompt.txt Normal file
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Write a custom CUDA kernel to optimize `torch.linalg.cross`.
The operation computes the cross product of two 3-dimensional vectors, batched over all other dimensions. The core formula for the output vector `c` from input vectors `a` and `b` is `c_1 = a_2*b_3 - a_3*b_2`, `c_2 = a_3*b_1 - a_1*b_3`, `c_3 = a_1*b_2 - a_2*b_1`.
**Problem Analysis:**
`torch.linalg.cross` is a classic memory-bandwidth-bound operation. Its arithmetic intensity is very low (9 floating-point operations per 9 floats of memory I/O). A potential PyTorch implementation might involve slicing, element-wise multiplication, and subtraction, which could create intermediate tensors and add overhead. Even with a fused kernel, the overhead of the general PyTorch dispatcher can be significant for such a lightweight operation.
**Optimization Strategy: Fused "One-Thread-per-Product" Kernel**
The strategy is to create a minimalist, fully-fused CUDA kernel that maps the cross-product logic directly to the hardware with minimal overhead.
1. **Parallelism Model**: The kernel is launched with one thread for every cross product to be computed. If the input shape is `(..., 3)`, the number of threads is `input.numel() / 3`. Each thread is completely independent.
2. **Fully Fused In-Register Computation**: Each thread is responsible for one entire cross product calculation:
a. It computes the base address for its assigned 3-element input vectors in `x` and `y`.
b. It loads all 6 required float values (3 from `x`, 3 from `y`) from global memory directly into its private registers.
c. It performs all 6 multiplications and 3 subtractions entirely within registers, which is extremely fast.
d. It writes the 3 resulting float values directly to the correct locations in the output tensor.
3. **Elimination of Overhead**: This approach constitutes a single pass over the data. It completely eliminates any intermediate tensors and bypasses the PyTorch dispatcher's general-purpose machinery, leading to a kernel whose performance is almost exclusively limited by the GPU's raw memory bandwidth.
Here's an example to show you the syntax of inline embedding custom CUDA operators in torch: The example given architecture is:
```python
import torch
import torch.nn as nn
import torch.nn.functional as F
class Model(nn.Module):
def __init__(self) -> None:
super().__init__()
def forward(self, a, b):
return a + b
def get_inputs():
# randomly generate input tensors based on the model architecture
a = torch.randn(1, 128).cuda()
b = torch.randn(1, 128).cuda()
return [a, b]
def get_init_inputs():
# randomly generate tensors required for initialization based on the model architecture
return []

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###########################################################
# 性能和精度验证程序
###########################################################
import torch
import torch.nn as nn
import time
from cross_torch import Model,get_inputs,get_init_inputs
from cross_cuda import ModelNew
def run_benchmark():
# 检查 CUDA 是否可用
if not torch.cuda.is_available():
print("CUDA 不可用,请确保您有可用的 NVIDIA GPU 并已正确安装 PyTorch CUDA 版本。")
return
else:
device = torch.device("cuda")
# 初始化模型
init_inputs = get_init_inputs()
init_inputs = [
x.cuda(device=device) if isinstance(x, torch.Tensor) else x for x in init_inputs
]
inputs = get_inputs()
inputs = [
x.cuda(device=device) if isinstance(x, torch.Tensor) else x for x in inputs
]
torch_model = Model(*init_inputs).cuda()
cuda_model = ModelNew(*init_inputs).cuda()
torch_model.eval()
cuda_model.eval()
print("-------------------- 精度对齐验证 --------------------")
with torch.no_grad():
output_torch = torch_model( *inputs)
output_cuda = cuda_model(*inputs)
precision_flag = torch.allclose(output_torch, output_cuda,rtol=1e-03)
if precision_flag:
print("✅ 精度对齐:两个模型的输出结果非常接近。")
else:
print("❌ 精度不一致!")
print("\n-------------------- 性能加速比测试 --------------------")
num_iterations = 100
# PyTorch 模型计时
torch.cuda.synchronize()
start_time = time.time()
for _ in range(num_iterations):
_ = torch_model(*inputs)
torch.cuda.synchronize()
torch_time = (time.time() - start_time) / num_iterations
# 自定义 CUDA 内核计时
torch.cuda.synchronize()
start_time = time.time()
for _ in range(num_iterations):
_ = cuda_model(*inputs)
torch.cuda.synchronize()
cuda_time = (time.time() - start_time) / num_iterations
print(f"PyTorch torch.relu 平均执行时间: {torch_time:.6f}")
print(f"自定义 CUDA 内核 平均执行时间: {cuda_time:.6f}")
speedup = 0
if cuda_time > 0:
speedup = torch_time / cuda_time
print(f"加速比 (Speedup): {speedup:.2f}x")
else:
print("CUDA 内核执行时间为0无法计算加速比。")
return precision_flag,speedup
if __name__ == "__main__":
precision_flag,speedup = run_benchmark()